WebFirst 30 multiples of 8 are8,16,24,… upto 30 terms It is an arithmetic sequence with the first term as 8, common difference=8, number of terms=30 a=8,d=8,n=30 We use the formula for Sn to find the sum of n terms Sn= (n/2) {2a+ (n-1)d} S30= (30/2) {2*8+ (30–1)*8} =15 (16+29*8) =15 (16+232) =15 (248) =3720 1 Katravath Devula Naik WebApr 3, 2024 · Then, the sum of the first 15 multiples of 8 $=\dfrac{15}{2}\times \left( 8+120 \right)=\dfrac{15}{2}\times 128=960$. Thus, the sum of the first 15 multiples of 8 is 960. Note: The problem is very easy to solve but the student should be careful while putting the values of different variables in the formulae to get the correct answer without any ...
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WebFind the sum of the first 15 multiples of 8. Solution: The sum of the first n terms of an AP is given by Sₙ = n/2 [2a + (n - 1) d] or Sₙ = n/2 [a + l]. Here, a is the first term, d is a … WebWhat Are the Multiples of 6? The product of 6 with any number is a multiple of 6. 6×1 = 6. 6×2 = 12. 6×3 = 18. We get successive multiples of 6 by skip counting. If we skip count 128 times by 6, we will get the 128th multiple of 6. i.e., 128×6 = 768. penny\u0027s com online shopping
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WebMar 4, 2016 · To find the sum of an arithmetic series, there are two separate formulas. The one we will use is sn = n 2 (2a + (n − 1)d) n, or the number of terms, is 30. d, the … Weba. How many integers from 1 through 1,000 are multiples of 2 or multiples of 9? b. Suppose an integer from 1 through 1,000 is chosen at random. Use the result of part (a) to find the probability that the integer is a multiple of 2 or a multiple of 9. c. How many integers from 1 through 1,000 are neither multiples of 2 nor multiples of 9? WebSep 15, 2024 · 1st 30 positive multiples of 8: 8, 16, 24, 32, 40, 48, 56, 64, 73, 80, 88, 96, 104, 112, 120, 128, 136, 144, 152, 160, 168, 176, 184, 192, 200, 208, 216, 224, 232, … penny\u0027s comforters and bedspreads