WebAnswer is 2184. (b) Since it's a bit string of 14 digits and there can be only digits 0 or 1, we need to select 7 0s and the rest would be 7 1s, so the number of permutations would be equal to \frac {14!} { (14-7)!}=14\cdot13\cdot12\cdot...\cdot8=17297280 (14−7)!14! = 14⋅13⋅12⋅... ⋅8 = 17297280 . The answer is 17297280. WebJan 13, 2011 · There are 120 bit strings of length 10 with exactly three 0s. Wiki User ∙ 2011-01-13 07:24:55 This answer is: Study guides Algebra 20 cards A polynomial of degree …
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WebNov 26, 2024 · The bit string is of length 10. Each bit can be in one of the two states, viz 0 or 1. Evaluating the count of bit strings for given cases: Case 1: Exactly three 0s Think of it as if there are 10 seats and 3 people to sit on. They're going to be 0s. 3 seats can be chosen from 10 seats in ways. WebInternet celebrity 223 views, 10 likes, 1 loves, 12 comments, 1 shares, Facebook Watch Videos from QVC: Spring calls for a closet refresh! Join... cytiva chromatography systems
permutations - How many bit strings of length 10 contains
WebHow many bit strings of length 10 are there? Ans: 210. 37. How many bit strings of length 10 begin with 1101? Ans: 26. 38. How many bit strings of length 10 have exactly six 0s? Ans: . 39. How many bit strings of length 10 have equal numbers of 0s and 1s? Ans: . 40. How many bit strings of length 10 have more 0s than 1s? Ans: . WebHow many bit strings of length 10 contain at least three 1s and at least three 0s? Solution: From the question it is given that strings of length 10 contain at least three 1s and at … WebThe total number of length 6 strings with no repetitions in which the first character is not a special character is: 36 · 39 · 38 · 37 · 36 · 35 How many strings are there over the set {a, b, c} that have length 10 in which no two consecutive characters are the same? binford petwellnessclinics.com